Two string are tied 2 m apart on a rod and on the other end a mass 200 g is tied as shown in fig. Each string is 1.25 m long. Find the tensions T 1 and T 2 if the rod is rotated with 60 rpm.
Text Solution
Verified by ExpertsThe correct answer is:
B
Resolve T 1 and T 2 .
Look into Fig. carefully
T 1 cos θ θ + T 2 cos θ θ = mr ω ω 2
T 1 sin θ θ = T 2 sin θ θ + mg
or (T 1 + T 2 ) (0.6) = 0.2 × (3/4)(2 π π ) 2
or T 1 + T 2 = 10
T 1 – T 2 = mg/sin θ θ = 0.2×10/0.8 = 2.5
Solving T 1 = 6.25 N and T 2 = 3.75 N
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